DBMS LAB 3 SOLUTION

Create table employee(emp_id number(5) primary key,emp_name varchar2(25));

SQL>desc employee;

Name                                      Null?    Type
………………………………………………………………………………………..
EMP_ID                                      NOT NULL          NUMBER(5)
EMP_NAME                                                         VARCHAR2(25)

Valid Test Data:

SQL>insert into employee values(&emp_id,’&emp_name’);
SQL>select * from employee;

EMP_ID         EMP_NAME
………………………………………………………….
10                 Robert
21                Coulthard
    30                 Fernando Alonso 
    39                 Kartikeyan
    87                  Kimmi                       

SQL>create table department(dept_id number(5) primary key,dept_name varchar2(20));

SQL>desc department;
Name                                Null?    Type
………………………………………………………………………………………..
DEPT_ID                           NOT NULL      NUMBER(5)
DEPT_NAME                                          VARCHAR2(20)

SQL>insert  into department values(&dept_id,’&dept_name’);
SQL>select * from department;

DEPT_ID                              DEPT_NAME
……………………………………………………………………………..
100                                                                      sales
101                                                                      accounts
102                                                                      administration
103                                                                      production
104                                                                      supervisor
       
SQL>create table paydetails(emp_id number(5) references employee(emp_id),dept_id number(5) reerences department(dept_id),basic number(7,2),deductions number(5,2),additions number(5,2),doj date);

SQL>desc paydetails;

Name                                      Null?               Type
………………………………………………………………………………………..
EMP_ID                                                      NUMBER(5)
DEPT_ID                                                    NUMBER(5)
BASIC                                                        NUMBER(7,2)
DEDUCTIONS                                              NUMBER(5,2)
ADDITIONS                                                NUMBER(5,2)
DOJ                                                           DATE

Different Data Sets:
SQL>insert into paydeatils values(&emp_id,&dept_id,
&basic,&deductions,&additions,&doj);

SQL>select * from paydeatils;

EMP_ID  DEPT_ID    BASIC    DEDUCTIONS      ADDITIONS   DOJ
…………………………………………………………………………………………………………………..
10         101           25023.12    43.09            71.23       08-JAN-93
21         100            10500.29    23.98            40.9         01-JAN-06 
30         102            6500.5        30.54             15            06-JUL-97
39         103            9700.45      32.78             65.09       08-AUG-03
87         104            15000         97.66             154.8       24-SEP-04

SQL>create table payroll(emp_id number(5)references employee(emp_id),pay_date date);
SQL>desc payroll;

Name                                      Null?    Type
………………………………………………………………………………………..
EMP_ID                                              NUMBER(5)
PAY_DATE                                          DATE

SQL>insert into payroll values(&emp_id,’&date’);

SQL>select * from payroll;
EMP_ID            PAY_DATE
………………………………………………………….
10                     31-JAN-06
21                     03-FEB-06         
30                     15-JAN-06
39                     27-JAN-06
87                     04-FEB-06
c) List the employee details department wise

SQL>select empid,deptid from paydet;

EMPID     DEPTID
…………………………
401                    500
402                    200
403                    600
404                    400
405                    1200

d)   List all the employee names who joined after particular date    

SQL>select e,empname from employee e,paydet p where e.empid=p.empid and p.doj>=’05-mar-06’;

EMPNAME
…………………
AVINASH
NITIN
PHALGUN

e)   List  the details of employees whose basic salary is between 10,000 and 20,000

sqL> Select empid,empname  from employee where salary between 10000 and 20000;

EMPID    EMPNAME
…………………………….
402                      AKHILA
403                      aaaaaaaa

EMPID    EMPNAME
…………………………….
AKHILA

f) Give a count of how many employees are working in each department
SQL>select count(empid),deptid from paydet group by deptid;

COUNT (EMPID)          DEPTID
………………………………………………………
1                      200       
1                      400
1                        500
1                        600
1                        1200


g) Give a names of the employees whose netsalary>10,000 

SQL> select empname from employee where empid in(select empid from paydet where basic-deduction>10000);

EMPNAME
………………
AVINASH
AKHILA
HARISH
NITIN
PHALGUN

h) List the  details for an employee_id=5

sql> select * from employee where empid=5;

empid                       empname
------------------------------------------
5                               Coulthard




i)    Create a view which lists out the emp_name, department, basic, dedeuctions, netsalary



j)    Create a view which lists the emp_name and his netsalary

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